Solve 4^-2*(-1/4)^2div(-20)(9)^0

$$4 ^ { - 2 } \times ( - \frac { 1 } { 4 } ) ^ { 2 } \div ( - 20 ) ( 9 ) ^ { 0 }$$

Evaluate

$$-\frac{1}{5120}=-0.000195312$$

Solution Steps

Calculate 4 to the power of -2 and get \frac{1}{16}.

$$\frac{\frac{1}{16}\left(-\frac{1}{4}\right)^{2}}{-20}\times 9^{0}$$

Calculate -\frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$\frac{\frac{1}{16}\times \frac{1}{16}}{-20}\times 9^{0}$$

Multiply \frac{1}{16} and \frac{1}{16} to get \frac{1}{256}.

$$\frac{\frac{1}{256}}{-20}\times 9^{0}$$

Express \frac{\frac{1}{256}}{-20} as a single fraction.

$$\frac{1}{256\left(-20\right)}\times 9^{0}$$

Multiply 256 and -20 to get -5120.

$$\frac{1}{-5120}\times 9^{0}$$

Fraction \frac{1}{-5120} can be rewritten as -\frac{1}{5120} by extracting the negative sign.

$$-\frac{1}{5120}\times 9^{0}$$

Calculate 9 to the power of 0 and get 1.

$$-\frac{1}{5120}$$

Factor

$$-\frac{1}{5120} = -0.0001953125$$