Solve for x
x\geq 20
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20+x\geq 40
Multiply both sides of the equation by 5. Since 5 is positive, the inequality direction remains the same.
x\geq 40-20
Subtract 20 from both sides.
x\geq 20
Subtract 20 from 40 to get 20.
Examples
Quadratic equation
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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