Solve for x
x=\frac{y}{2}+\frac{4}{3}
Solve for y
y=2x-\frac{8}{3}
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-6x=-8-3y
Subtract 3y from both sides.
-6x=-3y-8
The equation is in standard form.
\frac{-6x}{-6}=\frac{-3y-8}{-6}
Divide both sides by -6.
x=\frac{-3y-8}{-6}
Dividing by -6 undoes the multiplication by -6.
x=\frac{y}{2}+\frac{4}{3}
Divide -8-3y by -6.
3y=-8+6x
Add 6x to both sides.
3y=6x-8
The equation is in standard form.
\frac{3y}{3}=\frac{6x-8}{3}
Divide both sides by 3.
y=\frac{6x-8}{3}
Dividing by 3 undoes the multiplication by 3.
y=2x-\frac{8}{3}
Divide -8+6x by 3.
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