Solve for x
x=-\frac{3y}{4}+2
Solve for y
y=\frac{8-4x}{3}
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8-4x=3y
Swap sides so that all variable terms are on the left hand side.
-4x=3y-8
Subtract 8 from both sides.
\frac{-4x}{-4}=\frac{3y-8}{-4}
Divide both sides by -4.
x=\frac{3y-8}{-4}
Dividing by -4 undoes the multiplication by -4.
x=-\frac{3y}{4}+2
Divide 3y-8 by -4.
3y=8-4x
The equation is in standard form.
\frac{3y}{3}=\frac{8-4x}{3}
Divide both sides by 3.
y=\frac{8-4x}{3}
Dividing by 3 undoes the multiplication by 3.
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