Solve for x
x=\frac{8\left(y+3\right)}{3}
Solve for y
y=\frac{3\left(x-8\right)}{8}
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3x=24+8y
Add 8y to both sides.
3x=8y+24
The equation is in standard form.
\frac{3x}{3}=\frac{8y+24}{3}
Divide both sides by 3.
x=\frac{8y+24}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{8y}{3}+8
Divide 24+8y by 3.
-8y=24-3x
Subtract 3x from both sides.
\frac{-8y}{-8}=\frac{24-3x}{-8}
Divide both sides by -8.
y=\frac{24-3x}{-8}
Dividing by -8 undoes the multiplication by -8.
y=\frac{3x}{8}-3
Divide 24-3x by -8.
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