Solve for x
x=\frac{4y-1}{3}
Solve for y
y=\frac{3x+1}{4}
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3x=-1+4y
Add 4y to both sides.
3x=4y-1
The equation is in standard form.
\frac{3x}{3}=\frac{4y-1}{3}
Divide both sides by 3.
x=\frac{4y-1}{3}
Dividing by 3 undoes the multiplication by 3.
-4y=-1-3x
Subtract 3x from both sides.
-4y=-3x-1
The equation is in standard form.
\frac{-4y}{-4}=\frac{-3x-1}{-4}
Divide both sides by -4.
y=\frac{-3x-1}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{3x+1}{4}
Divide -1-3x by -4.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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