Solve 3x-4x^2+2y^2*4y^2-2x+8x^2

$$3x-4 { x }^{ 2 } +2 { y }^{ 2 } \times 4 { y }^{ 2 } -2x+8 { x }^{ 2 }$$

Evaluate

$$4x^{2}+x+8y^{4}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.

$$3x-4x^{2}+2y^{4}\times 4-2x+8x^{2}$$

Multiply 2 and 4 to get 8.

$$3x-4x^{2}+8y^{4}-2x+8x^{2}$$

Combine 3x and -2x to get x.

$$x-4x^{2}+8y^{4}+8x^{2}$$

Combine -4x^{2} and 8x^{2} to get 4x^{2}.

$$x+4x^{2}+8y^{4}$$

Differentiate w.r.t. x

$$8x+1$$