Solve for x
x=\frac{130-2y}{3}
Solve for y
y=-\frac{3x}{2}+65
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3x=130-2y
The equation is in standard form.
\frac{3x}{3}=\frac{130-2y}{3}
Divide both sides by 3.
x=\frac{130-2y}{3}
Dividing by 3 undoes the multiplication by 3.
130-2y=3x
Swap sides so that all variable terms are on the left hand side.
-2y=3x-130
Subtract 130 from both sides.
\frac{-2y}{-2}=\frac{3x-130}{-2}
Divide both sides by -2.
y=\frac{3x-130}{-2}
Dividing by -2 undoes the multiplication by -2.
y=-\frac{3x}{2}+65
Divide 3x-130 by -2.
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