3x= \frac{ 5(4y+3 }{ y }
Solve for x
x=\frac{20}{3}+\frac{5}{y}
y\neq 0
Solve for y
y=-\frac{15}{20-3x}
x\neq \frac{20}{3}
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3xy=5\left(4y+3\right)
Multiply both sides of the equation by y.
3xy=20y+15
Use the distributive property to multiply 5 by 4y+3.
3yx=20y+15
The equation is in standard form.
\frac{3yx}{3y}=\frac{20y+15}{3y}
Divide both sides by 3y.
x=\frac{20y+15}{3y}
Dividing by 3y undoes the multiplication by 3y.
x=\frac{20}{3}+\frac{5}{y}
Divide 20y+15 by 3y.
3xy=5\left(4y+3\right)
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.
3xy=20y+15
Use the distributive property to multiply 5 by 4y+3.
3xy-20y=15
Subtract 20y from both sides.
\left(3x-20\right)y=15
Combine all terms containing y.
\frac{\left(3x-20\right)y}{3x-20}=\frac{15}{3x-20}
Divide both sides by 3x-20.
y=\frac{15}{3x-20}
Dividing by 3x-20 undoes the multiplication by 3x-20.
y=\frac{15}{3x-20}\text{, }y\neq 0
Variable y cannot be equal to 0.
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Limits
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