Solve 3x+6-8y=z/V

$$3x+6-8y = \frac{ z }{ V }$$

Solve for V

$$\left\{\begin{matrix}V=-\frac{z}{-3x+8y-6}\text{, }&z\neq 0\text{ and }x\neq \frac{8y}{3}-2\\V\neq 0\text{, }&x=\frac{8y}{3}-2\text{ and }z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable V cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by V.

$$3xV+V\times 6-8yV=z$$

Combine all terms containing V.

$$\left(3x+6-8y\right)V=z$$

The equation is in standard form.

$$\left(3x-8y+6\right)V=z$$

Divide both sides by 3x+6-8y.

$$\frac{\left(3x-8y+6\right)V}{3x-8y+6}=\frac{z}{3x-8y+6}$$

Dividing by 3x+6-8y undoes the multiplication by 3x+6-8y.

$$V=\frac{z}{3x-8y+6}$$

Variable V cannot be equal to 0.

$$V=\frac{z}{3x-8y+6}\text{, }V\neq 0$$

Solve for x

$$x=\frac{8y}{3}+\frac{z}{3V}-2$$

$$V\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by V.

$$3xV+V\times 6-8yV=z$$

Subtract V\times 6 from both sides.

$$3xV-8yV=z-V\times 6$$

Add 8yV to both sides.

$$3xV=z-V\times 6+8yV$$

Multiply -1 and 6 to get -6.

$$3xV=z-6V+8yV$$

The equation is in standard form.

$$3Vx=8Vy+z-6V$$

Divide both sides by 3V.

$$\frac{3Vx}{3V}=\frac{8Vy+z-6V}{3V}$$

Dividing by 3V undoes the multiplication by 3V.

$$x=\frac{8Vy+z-6V}{3V}$$

Divide z-6V+8Vy by 3V.

$$x=\frac{8y}{3}+\frac{z}{3V}-2$$