Solve for x
x=-\frac{4y}{3}+40
Solve for y
y=-\frac{3x}{4}+30
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3x=120-4y
Subtract 4y from both sides.
\frac{3x}{3}=\frac{120-4y}{3}
Divide both sides by 3.
x=\frac{120-4y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{4y}{3}+40
Divide 120-4y by 3.
4y=120-3x
Subtract 3x from both sides.
\frac{4y}{4}=\frac{120-3x}{4}
Divide both sides by 4.
y=\frac{120-3x}{4}
Dividing by 4 undoes the multiplication by 4.
y=-\frac{3x}{4}+30
Divide 120-3x by 4.
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