Solve for x
x\leq 20
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3x\leq 64-4
Subtract 4 from both sides.
3x\leq 60
Subtract 4 from 64 to get 60.
x\leq \frac{60}{3}
Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.
x\leq 20
Divide 60 by 3 to get 20.
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