Solve for x
x=-\frac{2y}{3}+60
Solve for y
y=-\frac{3x}{2}+90
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3x=180-2y
Subtract 2y from both sides.
\frac{3x}{3}=\frac{180-2y}{3}
Divide both sides by 3.
x=\frac{180-2y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{2y}{3}+60
Divide 180-2y by 3.
2y=180-3x
Subtract 3x from both sides.
\frac{2y}{2}=\frac{180-3x}{2}
Divide both sides by 2.
y=\frac{180-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}+90
Divide 180-3x by 2.
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