Solve for x
x=\frac{19700-2z-2y}{3}
Solve for y
y=-\frac{3x}{2}-z+9850
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3x+2z=19700-2y
Subtract 2y from both sides.
3x=19700-2y-2z
Subtract 2z from both sides.
3x=19700-2z-2y
The equation is in standard form.
\frac{3x}{3}=\frac{19700-2z-2y}{3}
Divide both sides by 3.
x=\frac{19700-2z-2y}{3}
Dividing by 3 undoes the multiplication by 3.
2y+2z=19700-3x
Subtract 3x from both sides.
2y=19700-3x-2z
Subtract 2z from both sides.
2y=19700-2z-3x
The equation is in standard form.
\frac{2y}{2}=\frac{19700-2z-3x}{2}
Divide both sides by 2.
y=\frac{19700-2z-3x}{2}
Dividing by 2 undoes the multiplication by 2.
y=-\frac{3x}{2}-z+9850
Divide 19700-3x-2z by 2.
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