Solve 3x*4x=5

$$3x \times 4x=5$$

Solve for x

$$x=\frac{\sqrt{15}}{6}\approx 0.645497224$$

$$x=-\frac{\sqrt{15}}{6}\approx -0.645497224$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$3x^{2}\times 4=5$$

Multiply 3 and 4 to get 12.

$$12x^{2}=5$$

Divide both sides by 12.

$$x^{2}=\frac{5}{12}$$

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{15}}{6} x=-\frac{\sqrt{15}}{6}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$3x^{2}\times 4=5$$

Multiply 3 and 4 to get 12.

$$12x^{2}=5$$

Subtract 5 from both sides.

$$12x^{2}-5=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 12 for a, 0 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 12\left(-5\right)}}{2\times 12}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 12\left(-5\right)}}{2\times 12}$$

Multiply -4 times 12.

$$x=\frac{0±\sqrt{-48\left(-5\right)}}{2\times 12}$$

Multiply -48 times -5.

$$x=\frac{0±\sqrt{240}}{2\times 12}$$

Take the square root of 240.

$$x=\frac{0±4\sqrt{15}}{2\times 12}$$

Multiply 2 times 12.

$$x=\frac{0±4\sqrt{15}}{24}$$

Now solve the equation x=\frac{0±4\sqrt{15}}{24} when ± is plus.

$$x=\frac{\sqrt{15}}{6}$$

Now solve the equation x=\frac{0±4\sqrt{15}}{24} when ± is minus.

$$x=-\frac{\sqrt{15}}{6}$$

The equation is now solved.

$$x=\frac{\sqrt{15}}{6} x=-\frac{\sqrt{15}}{6}$$