Solve 3x*2x=540

$$3x \times 2x=540$$

Solve for x

$$x=3\sqrt{10}\approx 9.486832981$$

$$x=-3\sqrt{10}\approx -9.486832981$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$3x^{2}\times 2=540$$

Multiply 3 and 2 to get 6.

$$6x^{2}=540$$

Divide both sides by 6.

$$x^{2}=\frac{540}{6}$$

Divide 540 by 6 to get 90.

$$x^{2}=90$$

Take the square root of both sides of the equation.

$$x=3\sqrt{10} x=-3\sqrt{10}$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$3x^{2}\times 2=540$$

Multiply 3 and 2 to get 6.

$$6x^{2}=540$$

Subtract 540 from both sides.

$$6x^{2}-540=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 6 for a, 0 for b, and -540 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 6\left(-540\right)}}{2\times 6}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 6\left(-540\right)}}{2\times 6}$$

Multiply -4 times 6.

$$x=\frac{0±\sqrt{-24\left(-540\right)}}{2\times 6}$$

Multiply -24 times -540.

$$x=\frac{0±\sqrt{12960}}{2\times 6}$$

Take the square root of 12960.

$$x=\frac{0±36\sqrt{10}}{2\times 6}$$

Multiply 2 times 6.

$$x=\frac{0±36\sqrt{10}}{12}$$

Now solve the equation x=\frac{0±36\sqrt{10}}{12} when ± is plus.

$$x=3\sqrt{10}$$

Now solve the equation x=\frac{0±36\sqrt{10}}{12} when ± is minus.

$$x=-3\sqrt{10}$$

The equation is now solved.

$$x=3\sqrt{10} x=-3\sqrt{10}$$