Solve 37div6+14-6/2-7+45/54+49

$$37 \div 6+14- \frac{ 6 }{ 2 } -7+ \frac{ 45 }{ 5 } 4+49$$

Evaluate

$$\frac{571}{6}\approx 95.166666667$$

Solution Steps

Convert 14 to fraction \frac{84}{6}.

$$\frac{37}{6}+\frac{84}{6}-\frac{6}{2}-7+\frac{45}{5}\times 4+49$$

Since \frac{37}{6} and \frac{84}{6} have the same denominator, add them by adding their numerators.

$$\frac{37+84}{6}-\frac{6}{2}-7+\frac{45}{5}\times 4+49$$

Add 37 and 84 to get 121.

$$\frac{121}{6}-\frac{6}{2}-7+\frac{45}{5}\times 4+49$$

Divide 6 by 2 to get 3.

$$\frac{121}{6}-3-7+\frac{45}{5}\times 4+49$$

Convert 3 to fraction \frac{18}{6}.

$$\frac{121}{6}-\frac{18}{6}-7+\frac{45}{5}\times 4+49$$

Since \frac{121}{6} and \frac{18}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{121-18}{6}-7+\frac{45}{5}\times 4+49$$

Subtract 18 from 121 to get 103.

$$\frac{103}{6}-7+\frac{45}{5}\times 4+49$$

Convert 7 to fraction \frac{42}{6}.

$$\frac{103}{6}-\frac{42}{6}+\frac{45}{5}\times 4+49$$

Since \frac{103}{6} and \frac{42}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{103-42}{6}+\frac{45}{5}\times 4+49$$

Subtract 42 from 103 to get 61.

$$\frac{61}{6}+\frac{45}{5}\times 4+49$$

Divide 45 by 5 to get 9.

$$\frac{61}{6}+9\times 4+49$$

Multiply 9 and 4 to get 36.

$$\frac{61}{6}+36+49$$

Convert 36 to fraction \frac{216}{6}.

$$\frac{61}{6}+\frac{216}{6}+49$$

Since \frac{61}{6} and \frac{216}{6} have the same denominator, add them by adding their numerators.

$$\frac{61+216}{6}+49$$

Add 61 and 216 to get 277.

$$\frac{277}{6}+49$$

Convert 49 to fraction \frac{294}{6}.

$$\frac{277}{6}+\frac{294}{6}$$

Since \frac{277}{6} and \frac{294}{6} have the same denominator, add them by adding their numerators.

$$\frac{277+294}{6}$$

Add 277 and 294 to get 571.

$$\frac{571}{6}$$

Factor

$$\frac{571}{2 \cdot 3} = 95\frac{1}{6} = 95.16666666666667$$