Solve for x
x\leq -\frac{5}{3}
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36-8x+20x\leq 16
Add 20x to both sides.
36+12x\leq 16
Combine -8x and 20x to get 12x.
12x\leq 16-36
Subtract 36 from both sides.
12x\leq -20
Subtract 36 from 16 to get -20.
x\leq \frac{-20}{12}
Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.
x\leq -\frac{5}{3}
Reduce the fraction \frac{-20}{12} to lowest terms by extracting and canceling out 4.
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