Solve for x
x\leq -\frac{3}{2}
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34-8x+20x\leq 16
Add 20x to both sides.
34+12x\leq 16
Combine -8x and 20x to get 12x.
12x\leq 16-34
Subtract 34 from both sides.
12x\leq -18
Subtract 34 from 16 to get -18.
x\leq \frac{-18}{12}
Divide both sides by 12. Since 12 is positive, the inequality direction remains the same.
x\leq -\frac{3}{2}
Reduce the fraction \frac{-18}{12} to lowest terms by extracting and canceling out 6.
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