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a+b=13 ab=33\left(-8\right)=-264
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 33x^{2}+ax+bx-8. To find a and b, set up a system to be solved.
-1,264 -2,132 -3,88 -4,66 -6,44 -8,33 -11,24 -12,22
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -264.
-1+264=263 -2+132=130 -3+88=85 -4+66=62 -6+44=38 -8+33=25 -11+24=13 -12+22=10
Calculate the sum for each pair.
a=-11 b=24
The solution is the pair that gives sum 13.
\left(33x^{2}-11x\right)+\left(24x-8\right)
Rewrite 33x^{2}+13x-8 as \left(33x^{2}-11x\right)+\left(24x-8\right).
11x\left(3x-1\right)+8\left(3x-1\right)
Factor out 11x in the first and 8 in the second group.
\left(3x-1\right)\left(11x+8\right)
Factor out common term 3x-1 by using distributive property.
x=\frac{1}{3} x=-\frac{8}{11}
To find equation solutions, solve 3x-1=0 and 11x+8=0.
33x^{2}+13x-8=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-13±\sqrt{13^{2}-4\times 33\left(-8\right)}}{2\times 33}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 33 for a, 13 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-13±\sqrt{169-4\times 33\left(-8\right)}}{2\times 33}
Square 13.
x=\frac{-13±\sqrt{169-132\left(-8\right)}}{2\times 33}
Multiply -4 times 33.
x=\frac{-13±\sqrt{169+1056}}{2\times 33}
Multiply -132 times -8.
x=\frac{-13±\sqrt{1225}}{2\times 33}
Add 169 to 1056.
x=\frac{-13±35}{2\times 33}
Take the square root of 1225.
x=\frac{-13±35}{66}
Multiply 2 times 33.
x=\frac{22}{66}
Now solve the equation x=\frac{-13±35}{66} when ± is plus. Add -13 to 35.
x=\frac{1}{3}
Reduce the fraction \frac{22}{66} to lowest terms by extracting and canceling out 22.
x=-\frac{48}{66}
Now solve the equation x=\frac{-13±35}{66} when ± is minus. Subtract 35 from -13.
x=-\frac{8}{11}
Reduce the fraction \frac{-48}{66} to lowest terms by extracting and canceling out 6.
x=\frac{1}{3} x=-\frac{8}{11}
The equation is now solved.
33x^{2}+13x-8=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
33x^{2}+13x-8-\left(-8\right)=-\left(-8\right)
Add 8 to both sides of the equation.
33x^{2}+13x=-\left(-8\right)
Subtracting -8 from itself leaves 0.
33x^{2}+13x=8
Subtract -8 from 0.
\frac{33x^{2}+13x}{33}=\frac{8}{33}
Divide both sides by 33.
x^{2}+\frac{13}{33}x=\frac{8}{33}
Dividing by 33 undoes the multiplication by 33.
x^{2}+\frac{13}{33}x+\left(\frac{13}{66}\right)^{2}=\frac{8}{33}+\left(\frac{13}{66}\right)^{2}
Divide \frac{13}{33}, the coefficient of the x term, by 2 to get \frac{13}{66}. Then add the square of \frac{13}{66} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{13}{33}x+\frac{169}{4356}=\frac{8}{33}+\frac{169}{4356}
Square \frac{13}{66} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{13}{33}x+\frac{169}{4356}=\frac{1225}{4356}
Add \frac{8}{33} to \frac{169}{4356} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+\frac{13}{66}\right)^{2}=\frac{1225}{4356}
Factor x^{2}+\frac{13}{33}x+\frac{169}{4356}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{13}{66}\right)^{2}}=\sqrt{\frac{1225}{4356}}
Take the square root of both sides of the equation.
x+\frac{13}{66}=\frac{35}{66} x+\frac{13}{66}=-\frac{35}{66}
Simplify.
x=\frac{1}{3} x=-\frac{8}{11}
Subtract \frac{13}{66} from both sides of the equation.
x ^ 2 +\frac{13}{33}x -\frac{8}{33} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 33
r + s = -\frac{13}{33} rs = -\frac{8}{33}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{13}{66} - u s = -\frac{13}{66} + u
Two numbers r and s sum up to -\frac{13}{33} exactly when the average of the two numbers is \frac{1}{2}*-\frac{13}{33} = -\frac{13}{66}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{13}{66} - u) (-\frac{13}{66} + u) = -\frac{8}{33}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{8}{33}
\frac{169}{4356} - u^2 = -\frac{8}{33}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{8}{33}-\frac{169}{4356} = -\frac{1225}{4356}
Simplify the expression by subtracting \frac{169}{4356} on both sides
u^2 = \frac{1225}{4356} u = \pm\sqrt{\frac{1225}{4356}} = \pm \frac{35}{66}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{13}{66} - \frac{35}{66} = -0.727 s = -\frac{13}{66} + \frac{35}{66} = 0.333
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.