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33\lfloor 0+\frac{1}{5}\rfloor
Dividing 1 by 5 gives 0 and remainder 1. Rewrite \frac{1}{5} as 0+\frac{1}{5}.
33\times 0
The floor of a real number a is the largest integer number less than or equal to a. The floor of 0+\frac{1}{5} is 0.
0
Multiply 33 and 0 to get 0.