Solve for x
x=-\frac{45y}{32}-\frac{9}{8}
Solve for y
y=-\frac{32x}{45}-\frac{4}{5}
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32x+59=23-45y
Subtract 45y from both sides.
32x=23-45y-59
Subtract 59 from both sides.
32x=-36-45y
Subtract 59 from 23 to get -36.
32x=-45y-36
The equation is in standard form.
\frac{32x}{32}=\frac{-45y-36}{32}
Divide both sides by 32.
x=\frac{-45y-36}{32}
Dividing by 32 undoes the multiplication by 32.
x=-\frac{45y}{32}-\frac{9}{8}
Divide -36-45y by 32.
45y+59=23-32x
Subtract 32x from both sides.
45y=23-32x-59
Subtract 59 from both sides.
45y=-36-32x
Subtract 59 from 23 to get -36.
45y=-32x-36
The equation is in standard form.
\frac{45y}{45}=\frac{-32x-36}{45}
Divide both sides by 45.
y=\frac{-32x-36}{45}
Dividing by 45 undoes the multiplication by 45.
y=-\frac{32x}{45}-\frac{4}{5}
Divide -36-32x by 45.
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