Solve 325x+y+13=9

$$325 x + y + 13 = 9$$

Solve for x

$$x=\frac{-y-4}{325}$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$325x+13=9-y$$

Subtract 13 from both sides.

$$325x=9-y-13$$

Subtract 13 from 9 to get -4.

$$325x=-4-y$$

The equation is in standard form.

$$325x=-y-4$$

Divide both sides by 325.

$$\frac{325x}{325}=\frac{-y-4}{325}$$

Dividing by 325 undoes the multiplication by 325.

$$x=\frac{-y-4}{325}$$

Solve for y

$$y=-325x-4$$

Solution Steps

Subtract 325x from both sides.

$$y+13=9-325x$$

Subtract 13 from both sides.

$$y=9-325x-13$$

Subtract 13 from 9 to get -4.

$$y=-4-325x$$