Solve 320x+130x+70x-400x

$$320 x + 130 x + 70 x - 400 x$$

Evaluate

$$120x$$

Solution Steps

Combine 320x and 130x to get 450x.

$$450x+70x-400x$$

Combine 450x and 70x to get 520x.

$$520x-400x$$

Combine 520x and -400x to get 120x.

$$120x$$

Differentiate w.r.t. x

$$120$$

Steps Using Definition of a Derivative

Combine 320x and 130x to get 450x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(450x+70x-400x)$$

Combine 450x and 70x to get 520x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(520x-400x)$$

Combine 520x and -400x to get 120x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(120x)$$

The derivative of ax^{n} is nax^{n-1}.

$$120x^{1-1}$$

Subtract 1 from 1.

$$120x^{0}$$

For any term t except 0, t^{0}=1.

$$120\times 1$$

For any term t, t\times 1=t and 1t=t.

$$120$$