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30=x^{2}\times 145
Multiply x and x to get x^{2}.
x^{2}\times 145=30
Swap sides so that all variable terms are on the left hand side.
x^{2}=\frac{30}{145}
Divide both sides by 145.
x^{2}=\frac{6}{29}
Reduce the fraction \frac{30}{145} to lowest terms by extracting and canceling out 5.
x=\frac{\sqrt{174}}{29} x=-\frac{\sqrt{174}}{29}
Take the square root of both sides of the equation.
30=x^{2}\times 145
Multiply x and x to get x^{2}.
x^{2}\times 145=30
Swap sides so that all variable terms are on the left hand side.
x^{2}\times 145-30=0
Subtract 30 from both sides.
145x^{2}-30=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 145\left(-30\right)}}{2\times 145}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 145 for a, 0 for b, and -30 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 145\left(-30\right)}}{2\times 145}
Square 0.
x=\frac{0±\sqrt{-580\left(-30\right)}}{2\times 145}
Multiply -4 times 145.
x=\frac{0±\sqrt{17400}}{2\times 145}
Multiply -580 times -30.
x=\frac{0±10\sqrt{174}}{2\times 145}
Take the square root of 17400.
x=\frac{0±10\sqrt{174}}{290}
Multiply 2 times 145.
x=\frac{\sqrt{174}}{29}
Now solve the equation x=\frac{0±10\sqrt{174}}{290} when ± is plus.
x=-\frac{\sqrt{174}}{29}
Now solve the equation x=\frac{0±10\sqrt{174}}{290} when ± is minus.
x=\frac{\sqrt{174}}{29} x=-\frac{\sqrt{174}}{29}
The equation is now solved.