Solve for x
x\leq 3
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30x+200-20x\leq 230
Use the distributive property to multiply 20 by 10-x.
10x+200\leq 230
Combine 30x and -20x to get 10x.
10x\leq 230-200
Subtract 200 from both sides.
10x\leq 30
Subtract 200 from 230 to get 30.
x\leq \frac{30}{10}
Divide both sides by 10. Since 10 is positive, the inequality direction remains the same.
x\leq 3
Divide 30 by 10 to get 3.
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