Solve 30+160+12(x-20)leq10x

$$30 + 160 + 12 ( x - 20 ) \leq 10 x$$

Solve for x

$$x\leq 25$$

Solution Steps

Add 30 and 160 to get 190.

$$190+12\left(x-20\right)\leq 10x$$

Use the distributive property to multiply 12 by x-20.

$$190+12x-240\leq 10x$$

Subtract 240 from 190 to get -50.

$$-50+12x\leq 10x$$

Subtract 10x from both sides.

$$-50+12x-10x\leq 0$$

Combine 12x and -10x to get 2x.

$$-50+2x\leq 0$$

Add 50 to both sides. Anything plus zero gives itself.

$$2x\leq 50$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$x\leq \frac{50}{2}$$

Divide 50 by 2 to get 25.

$$x\leq 25$$