Solve 3-y=4x+6+y

$$3-y=4x+6+y$$

Solve for x

$$x=-\frac{y}{2}-\frac{3}{4}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$4x+6+y=3-y$$

Subtract 6 from both sides.

$$4x+y=3-y-6$$

Subtract 6 from 3 to get -3.

$$4x+y=-3-y$$

Subtract y from both sides.

$$4x=-3-y-y$$

Combine -y and -y to get -2y.

$$4x=-3-2y$$

The equation is in standard form.

$$4x=-2y-3$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{-2y-3}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{-2y-3}{4}$$

Divide -3-2y by 4.

$$x=-\frac{y}{2}-\frac{3}{4}$$

Solve for y

$$y=-2x-\frac{3}{2}$$

Steps for Solving Linear Equation

Subtract y from both sides.

$$3-y-y=4x+6$$

Combine -y and -y to get -2y.

$$3-2y=4x+6$$

Subtract 3 from both sides.

$$-2y=4x+6-3$$

Subtract 3 from 6 to get 3.

$$-2y=4x+3$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{4x+3}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{4x+3}{-2}$$

Divide 4x+3 by -2.

$$y=-2x-\frac{3}{2}$$