Solve 3(3x-1)leq7

$$3(3x-1) \leq 7$$

Solve for x

$$x\leq \frac{10}{9}$$

Solution Steps

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$3x-1\leq \frac{7}{3}$$

Add 1 to both sides.

$$3x\leq \frac{7}{3}+1$$

Convert 1 to fraction \frac{3}{3}.

$$3x\leq \frac{7}{3}+\frac{3}{3}$$

Since \frac{7}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$3x\leq \frac{7+3}{3}$$

Add 7 and 3 to get 10.

$$3x\leq \frac{10}{3}$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$x\leq \frac{\frac{10}{3}}{3}$$

Express \frac{\frac{10}{3}}{3} as a single fraction.

$$x\leq \frac{10}{3\times 3}$$

Multiply 3 and 3 to get 9.

$$x\leq \frac{10}{9}$$