Solve 3(-4)+3x-5

$$3(-4)+3x-5$$

Evaluate

$$3x-17$$

Solution Steps

Multiply 3 and -4 to get -12.

$$-12+3x-5$$

Subtract 5 from -12 to get -17.

$$-17+3x$$

Differentiate w.r.t. x

$$3$$

Steps Using Derivative Rule for Sum

Multiply 3 and -4 to get -12.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-12+3x-5)$$

Subtract 5 from -12 to get -17.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-17+3x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$3x^{1-1}$$

Subtract 1 from 1.

$$3x^{0}$$

For any term t except 0, t^{0}=1.

$$3\times 1$$

For any term t, t\times 1=t and 1t=t.

$$3$$