Solve 3+3*6/63

$$3+3 \times \frac{ 6 }{ 63 }$$

Evaluate

$$\frac{23}{7}\approx 3.285714286$$

Solution Steps

Reduce the fraction \frac{6}{63} to lowest terms by extracting and canceling out 3.

$$3+3\times \frac{2}{21}$$

Express 3\times \frac{2}{21} as a single fraction.

$$3+\frac{3\times 2}{21}$$

Multiply 3 and 2 to get 6.

$$3+\frac{6}{21}$$

Reduce the fraction \frac{6}{21} to lowest terms by extracting and canceling out 3.

$$3+\frac{2}{7}$$

Convert 3 to fraction \frac{21}{7}.

$$\frac{21}{7}+\frac{2}{7}$$

Since \frac{21}{7} and \frac{2}{7} have the same denominator, add them by adding their numerators.

$$\frac{21+2}{7}$$

Add 21 and 2 to get 23.

$$\frac{23}{7}$$

Factor

$$\frac{23}{7} = 3\frac{2}{7} = 3.2857142857142856$$