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3+2\sqrt{2}-\sqrt{2}+3\sqrt{5}-4-3\sqrt{5}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
3+\sqrt{2}+3\sqrt{5}-4-3\sqrt{5}
Combine 2\sqrt{2} and -\sqrt{2} to get \sqrt{2}.
-1+\sqrt{2}+3\sqrt{5}-3\sqrt{5}
Subtract 4 from 3 to get -1.
-1+\sqrt{2}
Combine 3\sqrt{5} and -3\sqrt{5} to get 0.