Solve 3+2/5-1/4+7/2

$$3+ \frac{ 2 }{ 5 } - \frac{ 1 }{ 4 } + \frac{ 7 }{ 2 }$$

Evaluate

$$\frac{133}{20}=6.65$$

Solution Steps

Convert 3 to fraction \frac{15}{5}.

$$\frac{15}{5}+\frac{2}{5}-\frac{1}{4}+\frac{7}{2}$$

Since \frac{15}{5} and \frac{2}{5} have the same denominator, add them by adding their numerators.

$$\frac{15+2}{5}-\frac{1}{4}+\frac{7}{2}$$

Add 15 and 2 to get 17.

$$\frac{17}{5}-\frac{1}{4}+\frac{7}{2}$$

Least common multiple of 5 and 4 is 20. Convert \frac{17}{5} and \frac{1}{4} to fractions with denominator 20.

$$\frac{68}{20}-\frac{5}{20}+\frac{7}{2}$$

Since \frac{68}{20} and \frac{5}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{68-5}{20}+\frac{7}{2}$$

Subtract 5 from 68 to get 63.

$$\frac{63}{20}+\frac{7}{2}$$

Least common multiple of 20 and 2 is 20. Convert \frac{63}{20} and \frac{7}{2} to fractions with denominator 20.

$$\frac{63}{20}+\frac{70}{20}$$

Since \frac{63}{20} and \frac{70}{20} have the same denominator, add them by adding their numerators.

$$\frac{63+70}{20}$$

Add 63 and 70 to get 133.

$$\frac{133}{20}$$

Factor

$$\frac{7 \cdot 19}{2 ^ {2} \cdot 5} = 6\frac{13}{20} = 6.65$$