Solve 3+18/4+18/12

$$3+ \frac{ 18 }{ 4 } + \frac{ 18 }{ 12 }$$

Evaluate

$$9$$

Solution Steps

Reduce the fraction \frac{18}{4} to lowest terms by extracting and canceling out 2.

$$3+\frac{9}{2}+\frac{18}{12}$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{6}{2}+\frac{9}{2}+\frac{18}{12}$$

Since \frac{6}{2} and \frac{9}{2} have the same denominator, add them by adding their numerators.

$$\frac{6+9}{2}+\frac{18}{12}$$

Add 6 and 9 to get 15.

$$\frac{15}{2}+\frac{18}{12}$$

Reduce the fraction \frac{18}{12} to lowest terms by extracting and canceling out 6.

$$\frac{15}{2}+\frac{3}{2}$$

Since \frac{15}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$\frac{15+3}{2}$$

Add 15 and 3 to get 18.

$$\frac{18}{2}$$

Divide 18 by 2 to get 9.

$$9$$

Factor

$$3^{2}$$