Solve 3z+1/6=4z+7/6

$$3 z + \frac { 1 } { 6 } = 4 z + \frac { 7 } { 6 }$$

Solve for z

$$z=-1$$

Steps for Solving Linear Equation

Subtract 4z from both sides.

$$3z+\frac{1}{6}-4z=\frac{7}{6}$$

Combine 3z and -4z to get -z.

$$-z+\frac{1}{6}=\frac{7}{6}$$

Subtract \frac{1}{6} from both sides.

$$-z=\frac{7}{6}-\frac{1}{6}$$

Since \frac{7}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.

$$-z=\frac{7-1}{6}$$

Subtract 1 from 7 to get 6.

$$-z=\frac{6}{6}$$

Divide 6 by 6 to get 1.

$$-z=1$$

Multiply both sides by -1.

$$z=-1$$