Solve for x
x=\frac{3\left(y-2\right)}{4}
Solve for y
y=\frac{4x}{3}+2
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-4x=6-3y
Subtract 3y from both sides.
\frac{-4x}{-4}=\frac{6-3y}{-4}
Divide both sides by -4.
x=\frac{6-3y}{-4}
Dividing by -4 undoes the multiplication by -4.
x=\frac{3y}{4}-\frac{3}{2}
Divide 6-3y by -4.
3y=6+4x
Add 4x to both sides.
3y=4x+6
The equation is in standard form.
\frac{3y}{3}=\frac{4x+6}{3}
Divide both sides by 3.
y=\frac{4x+6}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{4x}{3}+2
Divide 6+4x by 3.
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