Solve for x
x=\frac{3y-7}{2}
Solve for y
y=\frac{2x+7}{3}
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-2x-7=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
-2x=-3y+7
Add 7 to both sides.
-2x=7-3y
The equation is in standard form.
\frac{-2x}{-2}=\frac{7-3y}{-2}
Divide both sides by -2.
x=\frac{7-3y}{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{3y-7}{2}
Divide -3y+7 by -2.
3y-7=2x
Add 2x to both sides. Anything plus zero gives itself.
3y=2x+7
Add 7 to both sides.
\frac{3y}{3}=\frac{2x+7}{3}
Divide both sides by 3.
y=\frac{2x+7}{3}
Dividing by 3 undoes the multiplication by 3.
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