Solve 3y-2x+12=0

$$3 y - 2 x + 12 = 0$$

Solve for x

$$x=\frac{3\left(y+4\right)}{2}$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$-2x+12=-3y$$

Subtract 12 from both sides.

$$-2x=-3y-12$$

Divide both sides by -2.

$$\frac{-2x}{-2}=\frac{-3y-12}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x=\frac{-3y-12}{-2}$$

Divide -3y-12 by -2.

$$x=\frac{3y}{2}+6$$

Solve for y

$$y=\frac{2\left(x-6\right)}{3}$$

Steps for Solving Linear Equation

Add 2x to both sides. Anything plus zero gives itself.

$$3y+12=2x$$

Subtract 12 from both sides.

$$3y=2x-12$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{2x-12}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{2x-12}{3}$$

Divide -12+2x by 3.

$$y=\frac{2x}{3}-4$$