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y^{2}\left(3y+2\right)+7\left(3y+2\right)
Do the grouping 3y^{3}+2y^{2}+21y+14=\left(3y^{3}+2y^{2}\right)+\left(21y+14\right), and factor out y^{2} in the first and 7 in the second group.
\left(3y+2\right)\left(y^{2}+7\right)
Factor out common term 3y+2 by using distributive property. Polynomial y^{2}+7 is not factored since it does not have any rational roots.