Solve 3y=6sqrt{x^2-4}

$$3 y = 6 \sqrt { x ^ { 2 } - 4 }$$

Solve for y (complex solution)

$$y=2\sqrt{x^{2}-4}$$

Steps for Solving Linear Equation

The equation is in standard form.

$$3y=6\sqrt{x^{2}-4}$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{6\sqrt{x^{2}-4}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{6\sqrt{x^{2}-4}}{3}$$

Divide 6\sqrt{x^{2}-4} by 3.

$$y=2\sqrt{x^{2}-4}$$

Solve for y

$$y=2\sqrt{x^{2}-4}$$

$$|x|\geq 2$$

Steps for Solving Linear Equation

The equation is in standard form.

$$3y=6\sqrt{x^{2}-4}$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{6\sqrt{x^{2}-4}}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{6\sqrt{x^{2}-4}}{3}$$

Divide 6\sqrt{x^{2}-4} by 3.

$$y=2\sqrt{x^{2}-4}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{y^{2}+16}}{2}$$

$$x=\frac{\sqrt{y^{2}+16}}{2}\text{, }arg(y)<\pi \text{ or }y=0$$

Solve for x

$$x=-\frac{\sqrt{y^{2}+16}}{2}$$

$$x=\frac{\sqrt{y^{2}+16}}{2}\text{, }y\geq 0$$