Solve for x
x=\frac{3y}{4}-\frac{z}{2}
Solve for y
y=\frac{2\left(2x+z\right)}{3}
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4x+2z=3y
Swap sides so that all variable terms are on the left hand side.
4x=3y-2z
Subtract 2z from both sides.
\frac{4x}{4}=\frac{3y-2z}{4}
Divide both sides by 4.
x=\frac{3y-2z}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{3y}{4}-\frac{z}{2}
Divide 3y-2z by 4.
3y=4x+2z
The equation is in standard form.
\frac{3y}{3}=\frac{4x+2z}{3}
Divide both sides by 3.
y=\frac{4x+2z}{3}
Dividing by 3 undoes the multiplication by 3.
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Limits
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