Solve for x
x=\frac{3\left(y+1\right)}{2}
Solve for y
y=\frac{2x}{3}-1
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2x-3=3y
Swap sides so that all variable terms are on the left hand side.
2x=3y+3
Add 3 to both sides.
\frac{2x}{2}=\frac{3y+3}{2}
Divide both sides by 2.
x=\frac{3y+3}{2}
Dividing by 2 undoes the multiplication by 2.
3y=2x-3
The equation is in standard form.
\frac{3y}{3}=\frac{2x-3}{3}
Divide both sides by 3.
y=\frac{2x-3}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{2x}{3}-1
Divide 2x-3 by 3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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