Solve for x
x=\frac{3\left(y+40\right)}{10}
Solve for y
y=\frac{10\left(x-12\right)}{3}
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10x-120=3y
Swap sides so that all variable terms are on the left hand side.
10x=3y+120
Add 120 to both sides.
\frac{10x}{10}=\frac{3y+120}{10}
Divide both sides by 10.
x=\frac{3y+120}{10}
Dividing by 10 undoes the multiplication by 10.
x=\frac{3y}{10}+12
Divide 120+3y by 10.
3y=10x-120
The equation is in standard form.
\frac{3y}{3}=\frac{10x-120}{3}
Divide both sides by 3.
y=\frac{10x-120}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{10x}{3}-40
Divide -120+10x by 3.
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