Solve 3y+5-3x+2=20

$$3 y + 5 - 3 x + 2 = 20$$

Solve for x

$$x = -\frac{13}{3} = -4\frac{1}{3} = -4.333333333333333$$

Steps for Solving Linear Equation

Add 5 and 2 to get 7.

$$3y+7-3x=20$$

Subtract 3y from both sides.

$$7-3x=20-3y$$

Subtract 7 from both sides.

$$-3x=20-3y-7$$

Subtract 7 from 20 to get 13.

$$-3x=13-3y$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{13-3y}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{13-3y}{-3}$$

Divide 13-3y by -3.

$$x=y-\frac{13}{3}$$

Solve for y

$$y = \frac{13}{3} = 4\frac{1}{3} = 4.333333333333333$$

Steps for Solving Linear Equation

Add 5 and 2 to get 7.

$$3y+7-3x=20$$

Subtract 7 from both sides.

$$3y-3x=20-7$$

Subtract 7 from 20 to get 13.

$$3y-3x=13$$

Add 3x to both sides.

$$3y=13+3x$$

The equation is in standard form.

$$3y=3x+13$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{3x+13}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{3x+13}{3}$$

Divide 13+3x by 3.

$$y=x+\frac{13}{3}$$