Solve 3y+4z+6=0

$$3 y + 4 z + 6 = 0$$

Solve for y

$$y=-\frac{4z}{3}-2$$

Steps for Solving Linear Equation

Subtract 4z from both sides. Anything subtracted from zero gives its negation.

$$3y+6=-4z$$

Subtract 6 from both sides.

$$3y=-4z-6$$

Divide both sides by 3.

$$\frac{3y}{3}=\frac{-4z-6}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$y=\frac{-4z-6}{3}$$

Divide -4z-6 by 3.

$$y=-\frac{4z}{3}-2$$

Solve for z

$$z=-\frac{3y}{4}-\frac{3}{2}$$

Steps for Solving Linear Equation

Subtract 3y from both sides. Anything subtracted from zero gives its negation.

$$4z+6=-3y$$

Subtract 6 from both sides.

$$4z=-3y-6$$

Divide both sides by 4.

$$\frac{4z}{4}=\frac{-3y-6}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$z=\frac{-3y-6}{4}$$

Divide -3y-6 by 4.

$$z=-\frac{3y}{4}-\frac{3}{2}$$