Solve 3y+3x=5y+2z/4

$$3 y + 3 x = 5 y + \frac { 2 z } { 4 }$$

Solve for x

$$x=\frac{4y+z}{6}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$12y+12x=20y+2z$$

Subtract 12y from both sides.

$$12x=20y+2z-12y$$

Combine 20y and -12y to get 8y.

$$12x=8y+2z$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{8y+2z}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{8y+2z}{12}$$

Divide 8y+2z by 12.

$$x=\frac{z}{6}+\frac{2y}{3}$$

Solve for y

$$y=\frac{3x}{2}-\frac{z}{4}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 4.

$$12y+12x=20y+2z$$

Subtract 20y from both sides.

$$12y+12x-20y=2z$$

Combine 12y and -20y to get -8y.

$$-8y+12x=2z$$

Subtract 12x from both sides.

$$-8y=2z-12x$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{2z-12x}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{2z-12x}{-8}$$

Divide 2z-12x by -8.

$$y=\frac{3x}{2}-\frac{z}{4}$$