Solve for x
x=\frac{y+8}{3}
Solve for y
y=3x-8
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3x-8=y
Add y to both sides. Anything plus zero gives itself.
3x=y+8
Add 8 to both sides.
\frac{3x}{3}=\frac{y+8}{3}
Divide both sides by 3.
x=\frac{y+8}{3}
Dividing by 3 undoes the multiplication by 3.
-y-8=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-y=-3x+8
Add 8 to both sides.
-y=8-3x
The equation is in standard form.
\frac{-y}{-1}=\frac{8-3x}{-1}
Divide both sides by -1.
y=\frac{8-3x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x-8
Divide -3x+8 by -1.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}