Solve for x
x=\frac{y+9}{3}
Solve for y
y=3\left(x-3\right)
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3x=9+y
Add y to both sides.
3x=y+9
The equation is in standard form.
\frac{3x}{3}=\frac{y+9}{3}
Divide both sides by 3.
x=\frac{y+9}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{y}{3}+3
Divide 9+y by 3.
-y=9-3x
Subtract 3x from both sides.
\frac{-y}{-1}=\frac{9-3x}{-1}
Divide both sides by -1.
y=\frac{9-3x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x-9
Divide 9-3x by -1.
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