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3x+9=y
Add y to both sides. Anything plus zero gives itself.
3x=y-9
Subtract 9 from both sides.
\frac{3x}{3}=\frac{y-9}{3}
Divide both sides by 3.
x=\frac{y-9}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{y}{3}-3
Divide y-9 by 3.
-y+9=-3x
Subtract 3x from both sides. Anything subtracted from zero gives its negation.
-y=-3x-9
Subtract 9 from both sides.
\frac{-y}{-1}=\frac{-3x-9}{-1}
Divide both sides by -1.
y=\frac{-3x-9}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x+9
Divide -3x-9 by -1.