Solve for x
x=\frac{y-5z+15}{3}
Solve for y
y=3x+5z-15
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3x+5z=15+y
Add y to both sides.
3x=15+y-5z
Subtract 5z from both sides.
3x=y-5z+15
The equation is in standard form.
\frac{3x}{3}=\frac{y-5z+15}{3}
Divide both sides by 3.
x=\frac{y-5z+15}{3}
Dividing by 3 undoes the multiplication by 3.
x=\frac{y}{3}-\frac{5z}{3}+5
Divide 15+y-5z by 3.
-y+5z=15-3x
Subtract 3x from both sides.
-y=15-3x-5z
Subtract 5z from both sides.
-y=15-5z-3x
The equation is in standard form.
\frac{-y}{-1}=\frac{15-5z-3x}{-1}
Divide both sides by -1.
y=\frac{15-5z-3x}{-1}
Dividing by -1 undoes the multiplication by -1.
y=3x+5z-15
Divide 15-3x-5z by -1.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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